New Snakes

[EdgyExoticReptiles]

On tuesday I am getting 1.1 Anery Kenyan Sand Boas 66%poss. het for snow and a female high orange Kenyan Sand Boa. Sometime next week (probably tuesday) ill be getting 1.1 Red sideds het for anery from Tom. Ill have pictures u as soon as they are here.

[IndigoBug1987]

what is 1.1 and 66%poss?

[EdgyExoticReptiles]

1.1 means one male one female ( 1.0= one male 1.3= one male three females, 1.1.1 = one male one female one unknown)

66%poss het= 66% chance of being a het in this case it happened from a sand boa het for snow bred with a normal. 66% of the litter is het for snow but because you cant tell if something is a het its just a chance it might be.

[drache]

ooohh
Kenyan Sand Boas - pretty
looking forward to the photos

[jitami]

Looking forward to the pics Reed!

[aSnakeLovinBabe]

Reed, how did the breeder get 66% possible? If I am correct, you said the breeding was between a totally normal sand boa, and one that was "het snow" which actually means double heterozygous for Amelanic and Anerythristic. That would mean the normal parent's genotype would be AABB. The double het's genotype would be AaBb. When you line up these in a punnet square using each different combination of geners from each parent, you get the results that statistically, 1 in 4 or 25% of the offspring would have the genotype AaBb. 25% would be AABb, 25% would be AaBB, and 25% would be AABB, or completely normal. Then again, this is only statistically what will happen, what happens in real life is totally different. All the babies could be double het amel/anery, or all the babies could be het for nothing. There is simply no way to tell until you breed the animals.

But I am confused. Didn't you say the boas you are getting are anery? which would meant that they are possible het Amel (breeders like to say poss het snow it sounds better), meaning that one of the parents could absolutely not have been normal. It would have to have been an anery, or heterozygous for it. Both parents would have to either express or carry the anery gene in order for offspring to express it.

Maybe in your explanation you meant the parents were both anery's and one was het for amel? If so, you babies would be 50% possible hets for amel. I have started to wrack my brain so hard that I have now confused myself. could you please post the genetics of the parents of your snakes so i can have some peace of mind?! haha

I forget which scenario causes 66% of the phenotypically normal offspring to possibly be a het, but i know it's not this one

[EdgyExoticReptiles]

k ill check with the breeder and see how he got them im probaly wrong

Reed, how did the breeder get 66% possible? If I am correct, you said the breeding was between a totally normal sand boa, and one that was "het snow" which actually means double heterozygous for Amelanic and Anerythristic. That would mean the normal parent's genotype would be AABB. The double het's genotype would be AaBb. When you line up these in a punnet square using each different combination of geners from each parent, you get the results that statistically, 1 in 4 or 25% of the offspring would have the genotype AaBb. 25% would be AABb, 25% would be AaBB, and 25% would be AABB, or completely normal. Then again, this is only statistically what will happen, what happens in real life is totally different. All the babies could be double het amel/anery, or all the babies could be het for nothing. There is simply no way to tell until you breed the animals.

But I am confused. Didn't you say the boas you are getting are anery? which would meant that they are possible het Amel (breeders like to say poss het snow it sounds better), meaning that one of the parents could absolutely not have been normal. It would have to have been an anery, or heterozygous for it. Both parents would have to either express or carry the anery gene in order for offspring to express it.

Maybe in your explanation you meant the parents were both anery's and one was het for amel? If so, you babies would be 50% possible hets for amel. I have started to wrack my brain so hard that I have now confused myself. could you please post the genetics of the parents of your snakes so i can have some peace of mind?! haha

I forget which scenario causes 66% of the phenotypically normal offspring to possibly be a het, but i know it's not this one

[reptile3]

Congrats, can't wait to see pics!!

[count dewclaw]

Reed, how did the breeder get 66% possible? If I am correct, you said the breeding was between a totally normal sand boa, and one that was "het snow" which actually means double heterozygous for Amelanic and Anerythristic. That would mean the normal parent's genotype would be AABB. The double het's genotype would be AaBb. When you line up these in a punnet square using each different combination of geners from each parent, you get the results that statistically, 1 in 4 or 25% of the offspring would have the genotype AaBb. 25% would be AABb, 25% would be AaBB, and 25% would be AABB, or completely normal. Then again, this is only statistically what will happen, what happens in real life is totally different. All the babies could be double het amel/anery, or all the babies could be het for nothing. There is simply no way to tell until you breed the animals.

But I am confused. Didn't you say the boas you are getting are anery? which would meant that they are possible het Amel (breeders like to say poss het snow it sounds better), meaning that one of the parents could absolutely not have been normal. It would have to have been an anery, or heterozygous for it. Both parents would have to either express or carry the anery gene in order for offspring to express it.

Maybe in your explanation you meant the parents were both anery's and one was het for amel? If so, you babies would be 50% possible hets for amel. I have started to wrack my brain so hard that I have now confused myself. could you please post the genetics of the parents of your snakes so i can have some peace of mind?! haha

I forget which scenario causes 66% of the phenotypically normal offspring to possibly be a het, but i know it's not this one

Shannon, in this instance there are two different traits, so the Punet square would have 16 possible combinations. Statistically, 3 would be anery and of those 3, 2 are het for amel (but you can't tell which 2). Thus the 66% possible het for "snow". Hope that didn't muddy the waters further...

[aSnakeLovinBabe]

Shannon, in this instance there are two different traits, so the Punet square would have 16 possible combinations. Statistically, 3 would be anery and of those 3, 2 are het for amel (but you can't tell which 2). Thus the 66% possible het for "snow". Hope that didn't muddy the waters further...

aha!! now i remember! I was sitting there looking at my little drawn punnet square for a long time. It was late, and I was tired. I knew it was possible but could not remember for the life of me how it was figured.

I have a very good understanding of genetics, my senior year I actually taught my class the genetics stuff using snakes and color mutations as examples because I understood it 10x better than my own teacher! So she let me do it! I aced that class so sickenlingly well that my other classmates pretty much hated me

She eventually had me draw a punnet square of parent snakes carrying four different mutations for everyone.... sheesh that took forever